Using Henderson equition
"PH=pKa+log\\frac{A^-}{HA}\\\\6.5=7.21+log\\frac{A^-}{HA}\\\\log\\frac{A^-}{HA}=0.1950\\\\^-=0.1950(HA)"
Also
"(A^-)+(HA)=25mm\\\\0.1950(HA+(HA)=25mm\\\\(HA)=20.9208mm\\\\(A^-)=0.1950(HA)\\\\=4.0792"
Need: 3 L of 20.9206mm NaH2PO4
"M_1V_1=M_2V_2\\\\100mm\u00d7V=20.9206mm\u00d73L\\\\V=0.6276L\\\\=627.624ml"
Need: 3 L of 4.0792mm NaH2PO4
Similarly
"50mm\u00d7V=4.0792mm\u00d7300ml\\\\=244.75mL"
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