Answer to Question #208264 in Evolution for kenzie

Question

fifty heterozygous brown rabbits are placed with 100 homozygous white rabbits. what are the allele frequencies for brown fur (B) and for white fur (b)?

Answer 1

Answer:

p = frequency of the B allele becomes 0.7

q = frequency of the b allele = 0.3

Explanation:

Hardy Weinberg equation is used to calculate frequencies.

Hardy Weinberg equation can be written as p² + 2pq + q² = 1

Where

p² = frequency of homozygous dominant

p = frequency of B dominant allele

q² = frequency of homozygous recessive

q = frequency of b recessive allele

2pq = frequency of heterozygous dominant

According to given data

p² = frequency of homozygous dominant = 0.33

p becomes √0.33

p = frequency of the B allele becomes 0.57

Sum of both frequencies = 100% = p + q = 1

so q = 1 - p

q = 1 - 0.57

q = frequency of the b allele = 0.43