Answer to Question #313139 in Evolution for Nour

Question

If 51% of the population carries at least one copy of the recessive allele. what is the predicted frequency of the population expressing the dominant phenotype?

Answer 1

According to Hardy-Weinberg equations p+q=1 and p²+2pq+q²=1

Where p=frequency of dorminant allele

q=frequency of recessive allele

p²= frequency of heterozygous genotype

q²= frequency of recessive genotype

Since we do not have the frequency, we will first determine the value of p and q.

P² would be equal to 100-51%=49%

So p=0.7

Q=1-p. =1-0.7=0.3

The predicted frequency of individuals who express the dorminant phenotype are frequency of homozygous dorminant+ the frequency of heterozygous or p²+2pq

=0.7²+(2*0.7*0.3)

=0.49+0.42

=0.91

So the correct answer is 0.91