Answer to Question #276547 in Genetics for Water

Question

Following tetrads are observed in yeast crosses involving three pairs of  heterozygous genetic markers (A/a; B/b) (C/c; D/d) (E/e; F/f): 

Cross I (A/a; B/b) Cross II (C/c; D/d) Cross III (E/e; F/f) AB Ab CD CD EF Ef EF AB Ab CD Cd EF Ef Ef ab aB cd cD ef eF eF ab aB cd cd ef eF ef 

---- ----- ------ ----- ---- ----- ----  95 90 50 20 80 5 20  

What is the genetic map distance (in cM or M) between the two pairs of loci in each of the  three crosses?

Answer 1

95+90+20+80=285