the vapor pressure of H2O at 28 degrees Celsius is 28.3mmhg find the vapor pressure of a solution containing 100g of sugar c12H22011 in 500g of H20 at 28 degrees celcius.
M(sugar, C12H22O11) = 342 g/mole;
m(sugar, C12H22O11) = 100 g;
M(H2O) = 18 g/mole;
m(H2O) = 500 g;
P0 = 28.3mmHg;
n(sugar, C12H22O11) = m(sugar, C12H22O11)/M(sugar, C12H22O11) = 100/342 = 0.29 moles;
n(H2O) = m(H2O)/M(H2O) = 500/18 = 27.78 moles;
xi = n(H2O)/(n(H2O) + n(sugar, C12H22O11)) = 27.78/(27.78 + 0.29) = 27.78/28.07 = 0.9897
Psolution = xi * P0 = 0.9897 * 28.3 = 28.0 mmHg.
Answer: 28.0 mmHg.
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