If 3.0 mol CO reacts with 1.0 mol 02
2CO + O2 = 2CO2
CO excess reagent
O2 limiting reagent
n(CO2) = 2n(O2) = 2*1 mol = 2 mol
V(CO2) = 2*22.4= 44.8L
m(CO2) = 2 * 44 = 88 g
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