Answer to Question #330349 in General Chemistry for Kg master

General Chemistry

Question #330349

How many grams are in 0.2 moles of beryllium iodide, BeI2?

Expert's answer

m(BeI₂) = n(BeI₂) × Mr(BeI₂) = 0.2 mol × 262,821 g/mol = 52.56 g

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