Determine the [H+] , pH, and pOH of a solution with an [OH−] of 7.2×10−8 M at 25 °C.
[H+]=Â
pH=
pOH=
pOH = -lg[OH−] = -lg(7.2×10-8) = 7.14
pH = 14 - pOH = 14 - 7.14 = 6.86
[H+] = 10-pH = 10-6.86 = 1.38×10-7 M
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