Answer to Question #350662 in General Chemistry for Kell

Question

Calculate the reaction entropy (S°rxn) for the following reaction: NaCl + AgNO₃ >

AgCl + NaNO₃

Answer 1

S° (NaCl) = 72.13 J/mol•K

S° (AgNO₃) = 140.9 J/mol•K

S° (AgCl) = 96 J/mol•K

S° (NaNO₃) = 116.5 J/mol•K

Subtract the sum of the absolute entropies of the reactants from the sum of the absolute entropies of the products, each multiplied by their appropriate stoichiometric coefficients, to obtain ΔS° for the reaction.

NaCl = AgNO₃ = AgCl + NaNO₃

∆S° = S°_product – S°_reactant

∆S° = (96+116.5) - (72.35+141.04) = -0.88 J/mol•K

Answer: ∆S = -0.88 J/mol•K