Answer to Question #118567 in Inorganic Chemistry for josi

Question

how many moles are there in 51.1 g of NH3?

Answer 1

n(NH₃)= m(NH₃)/Mr(NH₃);

Mr(NH₃)=14+3=17 g/mol;

n(NH₃)=51.1/17=3 mol;

Answer: 3.0 mol of NH₃