The concentration of H+ of a solution of NaOH its POH is 11.3 is?
"pH + pOH = 14 \\\\\n\npH = 14 -11.3 = 2.7 \\\\\n\npH = -log[H^+] \\\\\n\n[H^+] = 10^{-pH} \\\\\n\n[H^+] = 10^{-2.7} \\\\\n\n[H^+] = 0.00199 \\;M"
Answer: 0.002 M
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment