How many moles of Fe are needed to combine with 24 moles of Cl2 by this reaction?Â
2Fe + 3Cl2 = 2FeCl3
n(Fe) = "\\frac{2}{3}"n(Cl2) = "\\frac{2}{3} \\times"24 = 16 (mol)
Answer: n(Fe) = 16 mol.
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