when 2.1g of a mixture Of KCLO3 and NaCl was thermally decomposed the mass of residue obtained was 1.62g. determine the mass of O2 liberated and calculate the mass if NaCl impurity in the original mixture
I. Since NaCl is stable to heat, only KClO3 decomposes.
2KClO3----> 2KCl + 3O2
Mass of mixture= 2.1g
Mass of residue= 1.62g
Mass of KClO3 that decomposed= 2.1g - 1.62g = 0.48g
Molar mass of KClO3= 122.5g/mol
Molar mass of O2= 32g/mol
From the balanced equation,
2(122.5)g of KClO3 yields 3(32)g of O2
0.48g of KCLO3 will yield 3(32)/2(122.5) x 0.48 = 0.19g of O2
II. To find the mass of NaCl impurity, let's find the mass of KCl in the residue.
Molar mass of KCl = 74.5g/mol
From the balanced equation,
122.5g of KClO3 yields 74.5g of KCl
0.48g of KClO3 will yield 74.5/122.5 x 0.48 = 0.29g of KCl
Mass of NaCl impurity= 1.62 - 0.29 = 1.33g
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