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Answer to Question #217971 in Organic Chemistry for Gowtham
Question #217971
0.5N h2so4, 25ml of sample, TV - 0.5
Meg/ltTV*N of h2so4 /ml of sample water
Hco3 in gr/lt=TV*N of h2so4 *eq. Wt. Hco3 (61)/ml of sample taken
What is the answer sir
Meg/ltTV*N of h2so4 /ml of sample water
Hco3 in gr/lt=TV*N of h2so4 *eq. Wt. Hco3 (61)/ml of sample taken
What is the answer sir
Expert's answer
Sample = "Sample=\\frac{0.5\u00d761}{25}=1.22N"
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