You want to create a 0.25 M KCl solution using 5.00 grams of Potassium Chloride. How much water is needed?
Molar mass of KCl "= 74.5513 g\/mol"
Moles of KCl "=\\frac{0.25}{74.5513}=0.0034moles"
Volume of water needed "=\\frac{0.0034}{0.25}=0.0134L"
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