Answer to Question #347789 in Organic Chemistry for Mfundo

Question

Assign oxidation numbers to all atoms, tell in each which substance is undergoing oxidation and which reduction

PbO2(s)+ Cl(aq)>PbCl2(s)+ O2(g)

Answer 1

Solution:

PbO₂(s) + 2Cl⁻(aq) → PbCl₂(s) + O₂(g)

Oxidation half-reaction:

2Cl⁻ − 2e⁻ → Cl₂⁰

Reduction half-reaction:

Pb⁴⁺ + 2e⁻ → Pb²⁺

Therefore,

Cl⁻(aq) undergoes oxidation

PbO₂(s) undergoes reduction