Cl2 (g) + 2OH- (aq) → ClO- (aq) + Cl- (aq) + H2O (l) Equation 1
2H+ (aq) + ClO- (aq) + 2I- (aq) → Cl- (aq) + I2 (aq) + H2O (l) Equation 2
I2 (aq) + I- (aq) → I3- (aq) Equation 3
I3- (aq) + 2S2O32- (aq) → 3I- (aq) + S4O62- (aq) Equation 4
The reaction of triiodide with thiosulfate produces the dithionate ion, S4O6 2-. Calculate the oxidation number for sulfur in this ion. Calculate (and show your work) the average oxidation number of S in this ion
Solution.
The average degree of sulfur oxidation based on calculations is +2.5:
"4 \\times x -12 = -2"
x = +2.5
However, due to the S-S bond, the oxidation state doubles. Thus, the oxidation state of the sulfur atom, which is connected to oxygen atoms, is +5.
Answer:
The average degree of sulfur oxidation based on calculations is +2.5.
However, due to the S-S bond, the oxidation state doubles. Thus, the oxidation state of the sulfur atom, which is connected to oxygen atoms, is +5.
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