Answer to Question #197323 in Chemistry for Emmanuel

Question

• How many grams of aluminum oxide are produced from the synthesis reaction of 30.0 g of Al ?
• Balance the equation= _ Al + O2 -> _ Al2O3
• Factor label( molar mass to mole , mole to mole ratio , mole to molar mass )

*This is one whole question *

Please & thank you.

Answer 1

Solution:

Balanced chemical equation:

4Al + 3O₂ → 2Al₂O₃

The molar mass of Al is 26.98 g/mol.

Therefore,

(30.0 g Al) × (1 mol Al / 26.98 g Al) = 1.112 mol Al

n(Al) = 1.112 mol

According to the equation: n(Al)/2 = n(Al₂O₃)

Therefore,

n(Al₂O₃) = n(Al)/2 = 1.112 mol / 2 = 0.556 mol Al₂O₃

The molar mass of Al₂O₃ is 101.96 g/mol.

Therefore,

(0.556 mol Al₂O₃) × (101.96 g Al₂O₃ / 1 mol Al₂O₃) = 56.6898 g Al₂O₃ = 56.7 g Al₂O₃

Answer: 56.7 g Al₂O₃