You need 8.0 mole of Na2Cr2O2 how much would this weigh?
Solution:
The molar mass of Na2Cr2O2 is 181.97 g/mol.
Therefore,
(8.0 mol Na2Cr2O2) × (181.97 g Na2Cr2O2 / 1 mol Na2Cr2O2) = 1455.76 g Na2Cr2O2
Answer: 1455.76 g Na2Cr2O2
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment