Answer to Question #227939 in Chemistry for Aki

Question

Calculate the value of the ionization constant K_b if the pK_b is 8.67

Answer 1

Solution:

pK_b = - log(K_b)

K_b = 10^-pKb

K_b = 10^-8.67 = 2.13×10^-9

K_b = 2.13×10^-9

Answer: The value of the ionization constant (K_b) is 2.13×10^-9