Answer to Question #257260 in Chemistry for sami

Question

for CH4(g) + 3Cl2(g) ——> CHCl3(g) + 3HCl(g) how many grams of CH4 is needed to produce 45.5 g CHCl3

Answer 1

Solution:

The molar mass of CH₄ is 16.04 g/mol

The molar mass of CHCl₃ is 119.38 g/mol

Calculate the moles of CHCl₃:

(45.5 g CHCl₃) × (1 mol CHCl₃ / 119.38 g CHCl₃) = 0.38 mol CHCl₃

Balanced chemical equation:

CH₄(g) + 3Cl₂(g) → CHCl₃(g) + 3HCl(g)

According to stoichiometry:

1 mol of CH₄ produces 1 mol of CHCl₃

x mol of CH₄ produces 0.38 mol of CHCl₃:

Thus,

x = (0.38 mol CHCl₃) × (1 mol CH₄ / 1 mol CHCl₃) = 0.38 mol CH₄

Calculate the mass of CH₄:

(0.38 mol CH₄) × (16.04 g CH₄ / 1 mol CH₄) = 6.0952 g CH₄ = 6.10 g CH₄

Answer: 6.10 grams of CH₄ is needed.