Answer to Question #350673 in Chemistry for Cow

Question

4. How many moles of Feliron)are produced with 3.45 moles of Mg(magnesium)?

3Mg + FezO - 2Fe + 3MgO

b. How many grams of Mg is that?

Answer 1

Solution:

Balanced chemical equation:

3Mg + Fe₂O₃ → 2Fe + 3MgO

According to stoichiometry:

3 mol of Mg produce 2 mol of Fe

Thus, 3.45 mol of Mg produce:

(3.45 mol Mg) × (2 mol Fe / 3 mol Mg) = 2.30 mol Fe

Moles of Fe = 2.30 mol

The molar mass of magnesium (Mg) is 24.3 g/mol

Therefore,

Mass of Mg = (3.45 mol Mg) × (24.3 g Mg / 1 mol Mg) = 83.835 g Mg = 83.8 g Mg

Mass of Mg = 83.8 g

Answer:

2.30 moles of iron (Fe) are produced

83.8 grams of Mg is that