3) Find the Laplace transform of 1-e^{-2t}/t
here F(ω)F(ω) is Laplace transform of f(t)f(t). We choose f(t)=(1−e−t)f(t)=(1−e−t) and it is easy to show that
F(s)=L[1−e−t]=1s−1s+1F(s)=L[1−e−t]=1s−1s+1
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