Answer to Question #191103 in Civil and Environmental Engineering for Joshua

Question

A binomial distribution consists of 120 trials, with a success probability of 43% . determine the mean and standard deviation

Answer 1

mean $\mu = np$

$\mu = 120 \times 0.43 = 51.6$

standard deviation= $\sigma$

$\sigma^2= np(1-p)= 120\times 0.43(1-0.43)$

$\sigma^2= 29.412$

$\sigma$ = $\sqrt{29.412}= 5.423$