Answer to Question #184267 in Engineering for dishdiossa

Question #184267

A ball is thrown vertically upwards from a platform 8 feet above the ground. After 2 seconds, the

ball is 2 feet below the platform. Find the initial velocity of the ball.

Expert's answer

"y=h+vt-0.5gt^2\\\\2=8+2v-0.5(32.174)(2)^2\\\\v=29.2\\frac{ft}{s}"

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