The first tern of an A.P. is 2 and the 6th term is 12. Find the
sum of the first 12 terms.
"a1 +(n-1)d.....Ap series"
"sum"
"sn = 0.5n(2a+(n-1)d)"
"a1 = 2"
"a1 + 5d = 12"
"d= 2"
"0.5*12(2*2 + (12-1)2)"
"sum = 156"
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