Answer to Question #244766 in Algebra for N1yxz

Question

If the polynomials x^3+ax^2+3x+5x and x^3 + 2x^2 + x + 2a leave the same remainder when divided by (x−1), then the value of a is:

Answer 1

$x-1=0=>x=1$

$$(1)^3+a(1)^2+3(1)+5=(1)^3+2(1)^2+1+2a$$

$$a+9=2a+4$$

$$a=5$$