Answer to Question #261186 in Algebra for Master J

Question #261186

Given that 𝑇 = 3√ 32𝑐4βˆ’π‘ž/2 . Show that 𝑐 = 1/2 4√2𝑇2 + π‘ž   


1
Expert's answer
2021-11-09T15:16:32-0500

T=32c4βˆ’q23=T3=32c4βˆ’q2=T3+q2=32c4=132(T3+q2)=c4=116β‹…12(2T3+q)=c4β€…β€ŠβŸΉβ€…β€Šc=1212(2T3+q)4T = \sqrt[3]{32c^4-\frac{q}{2}}\\ =T^3 = 32c^4-\frac{q}{2}\\ =T^3+\frac{q}{2}=32c^4\\ =\frac{1}{32}(T^3+\frac{q}{2})=c^4\\ =\frac{1}{16}\cdot\frac{1}{2}(2T^3+q)=c^4\\ \implies c = \frac{1}{2}\sqrt[4]{\frac{1}{2}(2T^3+q)}


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