Answer to Question #306943 in Algebra for Sinawo

Question #306943

Hence, write down the equation with y as the subject (in terms of x). The value of m and q must be indicated


1
Expert's answer
2022-03-07T21:22:01-0500

Solution


Consider the equation,


4xny2yxm=04x^ny - 2y -x^m=0


Here, mm and nn are constants.


To make the yy the subject and write in terms of "xx", we proceed as follows.


4xny2yxm=04x^ny - 2y -x^m=0


4xny2y=xm4x^ny - 2y=x^m


y(4xn2)=xmy(4x^n - 2) =x^m


y=xm4xn2y =\frac{x^m}{4x^n - 2}


y(x)=xm4xn2y(x) =\frac{x^m}{4x^n - 2}


Hence "yy", in terms of "xx " is


y(x)=xm4xn2{\color{Blue} y(x) =\frac{x^m}{4x^n - 2}\\}




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