Given Line L1: 3x-4y+3=0 and L2: 6x-8y+7=0 .
As clear both lines have the same slope m= 3/4, so given lines are parallell to each other.
a) So, Distance between given lines is
b) Now, the slope of perpendicular line to L1 is -1/m = -4/3 and given perpendicular line is passing through (-6,4).
So, the equation of perpendicular line is (y-4)=(-4/3)(x+6) .
c) Distance of line L1 from (-6,4) =
Distance of line L2 from(-6,4) =
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