We know that the centroid of the triangle (3x1β+x2β+x3ββ;3y1β+y2β+y3ββ)
Where (x1β;y1β);(x2β;y2β);(x3β;y3β) are the vertices of the
triangle SO, centroid= (3(β1)+1+0β;30+0+3β)=(30β;33β)=(0;1)
Hence, this is the answer.
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