Answer to Question #339416 in Analytic Geometry for alli

Question #339416

Find the centroid of the triangle whose vertices are (βˆ’1,0), (1,0), π‘Žπ‘›π‘‘ (0,3


1
Expert's answer
2022-05-15T10:48:59-0400

We know that the centroid of the triangle (x1+x2+x33;y1+y2+y33)(\frac{x_1+x_2+x_3}{3};\frac{y_1+y_2+y_3}{3})

Where (x1;y1);(x2;y2);(x3;y3)(x_1;y_1);(x_2;y_2);(x_3;y_3) are the vertices of the

triangle SO, centroid= ((βˆ’1)+1+03;0+0+33)=(03;33)=(0;1)(\frac{(-1)+1+0}{3};\frac{0+0+3}{3})=(\frac{0}{3};\frac{3}{3})=(0;1)

Hence, this is the answer.


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