If A=2xz^2i-yzj+3xz^3k then what is the value of curlA?
"Curl~A=\\begin{vmatrix}\n i & j & k \\\\\n \\frac{d}{dx} & \\frac{d}{dy} & \\frac{d}{dz}\\\\\n 2xz^2 & -yz & 3xz^3\n\\end{vmatrix}\n\\\\\ni(\\frac{d}{dy}(3xz^3)-\\frac{d}{dz}(-yz))-j(\\frac{d}{dx}(3xz^3)-\\frac{d}{dz}(2xz^2))+k(\\frac{d}{dx}(-yz)-\\frac{d}{dy}(2xz^2))\\\\\nCurl~A=i(y)-j(3z^3-4xz)+0k\\\\\nCurl~A=yi-(3z^3-4xz)j"
Comments
Leave a comment