Answer to Question #335263 in Calculus for gel

Question #335263

A spring exerts a force of 100 N when it is stretched 0.2 m beyond its natural length. How much work is required to stretch the spring 0.8 m beyond its natural length?

1
Expert's answer
2022-05-02T16:07:03-0400

F=kx

k=F/x=100/0.2=500

W=abkxdx=k00.8xdx=500(x2/2)00.8=500(0.82/202/2)=160W=\smallint^b_a kxdx=k\int^{0.8}_0xdx=500(x^2/2)|^{0.8}_0=500(0.8^2/2-0^2/2)=160



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