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Answer to Question #326636 in Complex Analysis for Janu
Question #326636
(1+3i÷2-5i)^2
Expert's answer
"(\\cfrac{1+3i}{2-5i})^2 = (\\cfrac{1*2 -5*1i+2*3i +3*5}{29})^2 =\\\\\n= (\\cfrac{17-i}{29})^2 = \\cfrac{288-34i}{841}"
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