Answer to Question #37128 in Differential Geometry for saba

Differential Geometry

Question #37128

find the tangent line of the curve at the points t=+1,-1,0
r(s)=(s^2-1,s(s^2-1),0)

Expert's answer

Download Answer

Learn more about our help with Assignments: Differential Geometry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. let r(s)=(x(s),y(s),0) be a unit speed curve prove that K=|x'y''-x''y'
2. let r(t)=(atcost,atsint,0) find the Frenet–Serret apparatus for regular curve?
3. Two pipes with circular cross-sections are subject to the constraint that the sum of their diameters
4. Three consecutive vertices of a parallelogram are points (2, 4), (0, 0), and (6, 0). The fourth vert
5. how can i find this slution E=〖(1+u^2+v^2)〗^2 from this x=u- 1/3 u^3+uv^2 y=-v-u^2 v+1/3 v^3
6. in a paralleogram abcd angle a= 50 degree b =?
7. A chord of a Circle is equal to the radius of the circle find the angle subtended by it at the centr