Answer to Question #275549 in Functional Analysis for Himanshu

Question #275549

Show that a norm on a vector space X is a sublinear functional on X




1
Expert's answer
2021-12-07T11:12:40-0500

Let’s 𝑓(π‘₯) = ||π‘₯||. Obviously, f(x) is a function from a vector space 𝑋 to the scalar field ℝ. 1. βˆ€π‘₯ ∈ 𝑋, βˆ€π‘Ž ∈ ℝ+, 𝑓(π‘₯) = ||π‘Ž βˆ™ π‘₯|| = |π‘Ž| βˆ™ ||π‘₯|| = π‘Ž βˆ™ ||π‘₯|| = π‘Ž βˆ™ 𝑓(π‘₯), due to the multiplicative property of a norm. 2. βˆ€π‘₯, 𝑦 ∈ 𝑋, 𝑓(π‘₯ + 𝑦) = ||π‘₯ + 𝑦|| ≀ ||π‘₯|| + ||𝑦|| = 𝑓(π‘₯) + 𝑓(𝑦), because of the triangle inequality. Correctness of the statement and both properties (positive homogeneity and subadditivity) were proved.


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