Answer to Question #175574 in Linear Algebra for william

Question #175574

solve the system of three variable linear equations

x + 2y = 1

3x + 2y + 4z = 7

-2x + y - 2z = -1



1
Expert's answer
2021-03-29T13:54:20-0400

The augmented matrix of the given system is:


[120:1324:7212:1]\begin{bmatrix} 1 & 2 &0:1\\ 3 & 2&4:7\\ -2&1&-2:-1 \end{bmatrix}

Now, R33R1R3;  R32R1+R3R_3\rightarrow3R_1-R_3;\ \ R_3\rightarrow2R_1+R_3

[120:1044:4052:1]\begin{bmatrix} 1 & 2 &0:1\\ 0 & 4&-4:4\\ 0&5&-2:1 \end{bmatrix}

R2R2/4;R_2\rightarrow R_2/4;

[120:1011:1052:1]\begin{bmatrix} 1 & 2 &0:1\\ 0 & 1&-1:1\\ 0&5&-2:1 \end{bmatrix}

R1R12R2;  R3R35R2R_1\rightarrow R_1-2R_2;\ \ R_3\rightarrow R_3-5R_2

[102:3011:1003:6]\Rightarrow \begin{bmatrix} 1 & 0 &2:3\\ 0 & 1&-1:1\\ 0&0&3:6 \end{bmatrix}

Comparing on third row,

3z=6[z=2]3z=6\Rightarrow [z=2]

On second row,


yz=1y=1+z[y=1]y-z=-1\Rightarrow y=-1+z\\ \Rightarrow [y=1]

On first row,


x=32z[x=1]x=3-2z\Rightarrow [x=-1]

[xyz]=[112]\Rightarrow\begin{bmatrix} x \\ y\\ z \end{bmatrix}=\begin{bmatrix} -1\\ 1\\ 2 \end{bmatrix}


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