Answer to Question #196878 in Linear Algebra for Mpopo

Question #196878

Compute all the minors and cofactors of

1 2 3

2 0 1

2 3 4


1
Expert's answer
2021-05-26T03:27:19-0400

A=[123201234]A=\begin{bmatrix} 1 & 2&3 \\ 2 & 0&1 \\ 2&3&4 \end{bmatrix}


Let MijM_{ij} stands for Minors and CijC_{ij} is cofactors

where i=ithi=i^{th} row and j=jthj=j^{th } column of the matrix


M11=0134=03=3   ;  C11=(1)1+1M11=3 M12=2124=82=6  ;  C12=(1)1+2M12=6 M13=2023=60=6  ;  C13=(1)1+3M13=6 M21=2334=89=1  ;  C13=(1)2+1M21=1 M22=1324=46=2  ;  C22=(1)2+2M22=2 M23=1223=34=1  ;  C23=(1)2+3M23=1 M31=2301=20=2  ;  C31=(1)3+1M31=2 M32=1321=16=5  ;  C32=(1)3+2M32=5 M33=1220=04=4  ;  C33=(1)3+3M33=4M_{11}=\begin{vmatrix} 0 & 1 \\ 3 & 4 \end{vmatrix}=0-3=-3\ \ \ ;\ \ C_{11}=(-1)^{1+1}M_{11}=-3\\\ \\M_{12}=\begin{vmatrix} 2 & 1 \\ 2 & 4 \end{vmatrix}=8-2=6\ \ ;\ \ C_{12}=(-1)^{1+2}M_{12}=-6\\\ \\M_{13}=\begin{vmatrix} 2 & 0 \\ 2 & 3 \end{vmatrix}=6-0=6\ \ ;\ \ C_{13}= (-1)^{1+3}M_{13}=6\\\ \\M_{21}=\begin{vmatrix} 2 & 3 \\ 3 & 4 \end{vmatrix}=8-9=-1\ \ ;\ \ C_{13}=(-1)^{2+1}M_{21}=1\\\ \\M_{22}=\begin{vmatrix} 1 & 3 \\ 2 & 4 \end{vmatrix}=4-6=-2\ \ ;\ \ C_{22}=(-1)^{2+2}M_{22}=-2\\\ \\M_{23}=\begin{vmatrix} 1 & 2 \\ 2 & 3 \end{vmatrix}=3-4=-1\ \ ;\ \ C_{23}=(-1)^{2+3}M_{23}=1\\\ \\M_{31}=\begin{vmatrix} 2 & 3 \\ 0 & 1 \end{vmatrix}=2-0=2\ \ ;\ \ C_{31}=(-1)^{3+1}M_{31}=2 \\\ \\M_{32=}\begin{vmatrix} 1 & 3 \\ 2 & 1 \end{vmatrix}=1-6=-5\ \ ;\ \ C_{32}=(-1)^{3+2}M_{32}=5\\\ \\M_{33}=\begin{vmatrix} 1 & 2 \\ 2 & 0 \end{vmatrix}=0-4=-4\ \ ;\ \ C_{33}=(-1)^{3+3}M_{33}=-4




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