Given:
"\\mu=1.2poise=0.12N\\cdot s\/m^2"
Diameter of shaft "D=10cm=0.1m"
Distance between shaft and journal bearing "dy=1.0mm=10^{-3}m"
Speed of shaft "N=200\\ r.p.m."
Tangential speed of shaft is given by
Change of velocity between shaft and bearing
Mathematically
"=40\\pi N\/m^2\\approx125.6637 N\/m^2"
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