A pyramidal monument has an octagonal base, each side of which is 2 m. Each lateral edge of the pyramid is 3m. Find the total cost of painting the lateral surface of the monument at PhP (Philippine Pesos) 730.00 per square meter?
FINAL ANSWER: _______________________________________
1
Expert's answer
2020-12-10T13:58:37-0500
A pyramidal monument has an octagonal base, each side is 2m. Hence BC=DC=DE=EF=FG=GH=HI=IB=2m
Lateral edge of pyramid = AB=AC=AD=AE=AF=AG=AH=AI=3m
Now in Δ ABC AB=AC=3m, AP _|_ BC
Hence BP = PC=2/2=1m
AC2=AP2+PC232=AP2+I2⟹9=AP2+1⟹9−1=AP2
Hence AP2=8⟹AP=8=2∗2
Now ar of Δ ABC = 1/2*base*heihght = 1/2 * BC * AP = 1/2∗2∗2∗2=22m2
Now lateral surface area of pyramid = 8∗22=162m2
Cost of painting the lateral surface of monument is: 162∗730=16517.86
Comments
Leave a comment