Answer to Question #166717 in Classical Mechanics for Rica

Question #166717

Dr. John Paul Stapp was U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s, and was brought jarringly back to rest in only 1.40 s!


1
Expert's answer
2021-02-25T11:23:30-0500

Given,

Initial velocity (vi)=0(v_i)=0

Final velocity (vf)=282m/s(v_f)=282 m/s

Time taken (t)=5.0sec(t)=5.0 sec

Acceleration of the particle (a)=vfvit(a) = \frac{v_f-v_i}{t}

Now, substituting the values,

a=2825m/s2a=\frac{282}{5} m/s^2

a=56.4m/s2\Rightarrow a = 56.4 m/s^2

Acceleration in terms of g ,

ag=56.4g9.8=5gm/s2a_g= \frac{56.4g}{9.8}=5g m/s^2

It comes in rest in 1.4s so retardation ar=2821.4m/s2a_r= \frac{-282}{1.4} m/s^2

=201.43m/s2=201.43 m/s^2

Retardation in terms of g,

arg=201.43g9.8m/s2a_{rg}=\frac{201.43g}{9.8} m/s^2


=20.5gm/s2=-20.5g m/s^2


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