A box is pulled on level ground by a force of 40 N that makes 45° with the ground.
Find a) the force that tends to lift the box, and b) the force that tends to pull the box forward.
expand the force F into vertical and horizontal projections\text{expand the force F into vertical and horizontal projections}expand the force F into vertical and horizontal projections
F⃗=F⃗∗cosα+F⃗∗sinα\vec{F}= \vec{F}*\cos\alpha+\vec{F}*\sin\alphaF=F∗cosα+F∗sinα
a) the force that tends to lift the box is F⃗∗cosα=40∗12≈28.3J\text{a) the force that tends to lift the box is } \vec{F}*\cos\alpha= 40*\frac{1}{\sqrt2}\approx28.3 Ja) the force that tends to lift the box is F∗cosα=40∗21≈28.3J
b) the force that tends to pull the box forward isF⃗∗sinα=40∗12≈28.3J\text{b) the force that tends to pull the box forward is}\vec{F}*\sin\alpha= 40*\frac{1}{\sqrt2}\approx28.3 Jb) the force that tends to pull the box forward isF∗sinα=40∗21≈28.3J
Answer:a) 28.3J b) 28.3J
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