2.Two charges q1 and q2 are separated by a distance 0.02mm in the air. The force between them is 100N. What will be the force between the q1 and q2 place 0.06mm apart in the air.
1) "|F|= \\frac{kq,q_2}{d^2}=\\frac{9*10^9*14*10^{-9}*23*10^{-9}}{0.06^2}"
"=\\frac{9*14*23*10^9}{0.06^2}"
"=80.5000*10^9N"
"=8.05*10^{14}N"
2) "F_1= \\frac{kq_1q_2}{d^2}"
"100= \\frac{9*10^9(q_1,q_2)}{(\\frac{0.02}{1000})^2}"
"=|q_1q_|=444.4*10^{-20}"
"F_2=\\frac{9*10^9*444.4*10^{-20}}{(\\frac{0.06}{1000})^2}"
"F\n_2=11.11N"
Comments
Leave a comment