Answer to Question #307921 in Electricity and Magnetism for percy

Question #307921

What is the electric field due to a point charge of 20µC at a distance of 1 meter away from it?

How much charge experiences a force of 5.0 x10-3 N due to an electric field of 10 N/C?


1
Expert's answer
2022-03-08T17:02:34-0500

Electric field

E=kqr²E=\frac{kq}{r^²}


E=9×109×20×10612=18×104N/CE=\frac{9\times10^9\times20\times10^{-6}}{1^2}=18\times10^4N/C

Force

F=qEF=qE

q=FEq=\frac{F}{E}

q=5×10310=5×104Cq=\frac{5\times10^{-3}}{10}=5\times10^{-4}C


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