Answer to Question #128649 in Field Theory for Onyi Emodi

Question #128649
a proton (charge +e = ) moves in a straight line from point a to point b inside a linear accelerator , a total distance d= 0.50m. the electric field is uniform along the line with
magnitude E = i.
. In the direction from a to b determine the force on the proton?
the work done on it by the field?
ii.
iii. thepotentialdifference ?
1
Expert's answer
2020-08-10T19:54:51-0400

i)


F=qE=(1.61019)(1.5107)=2.41012 NF=qE=(1.6\cdot10^{-19})(1.5\cdot10^{7})=2.4\cdot10^{-12}\ N

ii)


W=qEd=(1.61019)(1.5107)(0.5)=1.21012 JW=qEd=(1.6\cdot10^{-19})(1.5\cdot10^{7})(0.5)\\=1.2\cdot10^{-12}\ J

iii)


U=Ed=(1.5107)(0.5)=0.75107 VU=Ed=(1.5\cdot10^{7})(0.5)=0.75\cdot10^{7}\ V


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