Calculate the magnitude and direction of the electric field 0.45 m from a +7.85 x 10–9 C point charge.
Answer
Electric field is given by
"E=\\frac{KQ}{r^2}\\\\=\\frac{9*10^9**7.85*10^{-9}}{(0.45)^2}\\\\=348.89N\/m"
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