An object of mass moves round a circle of radius 6 m if the if the period of motion is π calculate the force towards the centre
Assume that "m=5\\ kg" . So, we have
"F=mv^2\/r=m\\omega^2r=m(\\frac{2\\pi}{T})^2r=m(\\frac{2\\pi}{\\pi})^2r="
"=4mr=4\\cdot5\\cdot6=120\\ (N)" . Answer
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