A Carnot cycle has a thermal efficiency of 32%. If the work developed is 1000 watt-hour, determine the heat supplied.
Given quantities:
"\\eta = 0.32 \\space \\space \\space A_1=1000 \\space \\space \\space A_2-?"
"\\eta = \\large\\frac{A_1-A_2}{A_1} \\to" "A_2 = A_1(1-\\eta)=1000(1-0.32)=680"
Answer: 680 watt-hour
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