Answer to Question #275322 in Mechanics | Relativity for JMD

Question #275322

Respectfully, the answer provided to my question #274901 does not address the question I asked.

Can we say, from special relativity, that since the accelerating force was applied to object B, that the clock in B will, in reality, tick more slowly than the clock in A?

Please disregard the effects of gravity for this scenario.

Thank you.


1
Expert's answer
2021-12-06T09:43:50-0500

After compensating for varying signal delays due to the changing distance between an observer and a moving clock (i.e. Doppler effect), the observer will measure the moving clock is ticking slower than a clock that is at rest in the observer's own reference frame.

So, the clock in B will, in reality, tick more slowly than the clock in A.


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Comments

JMD
06.12.21, 17:32

Thank you

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