If oil flows out of a pipe at the speed of 2.65m/s and the diameter of the pipe is 5.0cm, determine the discharge rate?
radius of the pipe="5\/2=2.5cm=0.025m"
cross-section area of the pipe"=\\pi r^2=3.142\\times 0.025^2 =0.001964m^2"
discharge rate=speed of flow "\\times" cross-section area="2.65\\times 0.001964=0.005205m^3\/s"
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